#include <stdio.h>
#include <stdlib.h>


// Copy the elements of one array into another using pointers

// This buggy program still works but but it demonstrates some of
// the dangers with using pointers.
int main()
{
	int *ip1, *ip2;
	int i;
	
	int a[5] =   {1, 3, 4, 5, 6};
	int b[5]; // {?, 1, 3, 4, 5}; + 6  (<--out of bounds assignment) // this will be the result after copying
	
//	for(i=0; i<5; i++)  // This is how we can do it without pointers
//		b[i] = a[i];
		
	ip1 = &a[0];
	ip2 = &b[1]; // *ip2 now points to b[1] and is thus off by one
	
	for(i=0; i<5; i++)  // copy the array
		*(ip2+i)  = *(ip1+i);
		
	for(i=0; i<5; i++)  // print the copy
		printf("%d, ", *(ip2+i) /*b[i]*/);
	system("pause");
}